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4x^2+37x+16=0
a = 4; b = 37; c = +16;
Δ = b2-4ac
Δ = 372-4·4·16
Δ = 1113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{1113}}{2*4}=\frac{-37-\sqrt{1113}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{1113}}{2*4}=\frac{-37+\sqrt{1113}}{8} $
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